# Notes on Failing to Understand Software Transactional Memory

Posted on May 22, 2016

I am writing some library to easily implement event sourced services in Haskell based on previous experience at Capital Match, and while doing so I rewrote a simple file-based event store. This store communicates with core service using TBQueue, a bounded queue implemented over Haskell’s STM. It took me couple of hours on Friday to solve a BlockedIndefinitelyOnSTM bug I was facing while testing this simple store. So today I posted a question about STM on Stack Overflow, as I did not have a clear intuition on why my code was failing, hence why my fix was correct.

The code of the store boils down to the following simple model.

First some useful imports…

{-# LANGUAGE ScopedTypeVariables #-}
module Main where

import           Control.Concurrent.Async
import           Control.Concurrent.STM
import           Control.Exception
import           Hevents.Eff
import           System.IO

The store dequeues some operation from a given queue, writes the operation’s string to stdout then put back the length of the written string into a TMVar, which models communicating the result of the operation back to the caller.

data Op = Op String (TMVar Int)

storerun :: TBQueue Op -> IO ()
storerun q = do
hSetBuffering h NoBuffering
forever $do Op s v <- atomically$ readTBQueue q
hPutStrLn h s
atomically $putTMVar v (length s) The main function is responsible for creating the jobs queue, starting the “store” in a separate thread then reading lines from stdin and feeding them as “operations” for the store. main :: IO () main = do q <- newTBQueueIO 100 _ <- async$ storerun q
storeInput q
where
storeInput q = forever $do l <- getLine v <- newEmptyTMVarIO r <- atomically$ do
writeTBQueue q (Op l v)
takeTMVar v

This code deadlocks because STM are actually - surprise! - transactions: They do all of their operations, or nothing, and they are serialized. Hence the following block:

r <- atomically $do writeTBQueue q (Op l v) takeTMVar v …can succeeds if and only if it can atomically put an operation in the queue and read the result back from v. Which of course is not possible because the result is put back after the operation is read from the queue in another transaction. The correct code is: atomically$ writeTBQueue q (Op l v)
r <- atomically \$ takeTMVar v

Pretty obvious, in retrospect. As the person who answered my question on SO, there is no way for two STM transactions to exchange information.